等待请求完成，然后再执行下一个操作

我想知道在执行另一段代码之前，如何等待发送请求的操作以完成上传（并获得响应）。我尝试使用NSOperations做到这一点：

    let testOp = BlockOperation {
        var result = 0

        for i in 1...1000000000 {
            result += i
        }
    }

    let logOp = BlockOperation {
        self.debug.log(tag: "test", content: "testing")
    }

    logOp.completionBlock = {
        print("------- logOp completed")
    }

    logOp.addDependency(testOp)

    let sendOp = BlockOperation {
        self.debug.sendLog() //uploads log, using URLSession.shared.dataTask
    }

    sendOp.completionBlock = {
        print("------- sendOp completed")
    }

    sendOp.addDependency(logOp)

    let emptyOp = BlockOperation {
        self.debug.empty()
    }

    emptyOp.completionBlock = {
        print("------- emptyOp completed")
    }

    emptyOp.addDependency(sendOp)

    let queue = OperationQueue()
    queue.addOperations([testOp, logOp, sendOp, emptyOp], waitUntilFinished: false)

输出：

------- logOp completed
*** Sending debug log (coming from self.debug.sendLog())
------- sendOp completed
------- emptyOp completed
*** sendLog uploaded (coming from self.debug.sendLog())

根据我的代码，我希望输出为：

------- logOp completed
*** Sending debug log
*** sendLog uploaded
------- sendOp completed
------- emptyOp completed

我该怎么做？我可以使用NSOperations做到这一点吗？

有关debug.sendLog（）函数的其他详细信息：

func sendLog() {
    ...
    var urlRequest = URLRequest(url: url!)
    urlRequest.httpMethod = "POST"
    ...

    let session = URLSession.shared
    let task = session.dataTask(with: urlRequest, completionHandler: {
        (data, response, error) in

        ...

        DispatchQueue.main.async {
            print("*** sendLog uploaded")

        }
    })

    task.resume()
}