我试图编写一个简单的程序,计算用户输入的字符串中的元音,辅音和空格的数量。我的do while循环和if语句出现问题。它会将所有内容都视为一个空间,而不是元音或辅音。如果您有任何建议,请告诉我!:)
import java.util.Arrays;
import java.util.HashSet;
import java.util.Set;
import javax.swing.JOptionPane;
public class VowelCounter {
private static final Set<String>
vowels = new HashSet<>
(Arrays.asList("a","e","i","o","u","y"));
private static final Set<String>
cons = new HashSet<>
(Arrays.asList("b","c","d","f","g","h","j","k","l","m","n","p","q","r","s","t","v","w","x","z"));
public static void main(String[] args) {
// ---------------------------------------------- VARIABLE DECLARATIONS
int vnum = 0;
int snum = 0;
int cnum = 0;
int i = 0;
// -------------------------------------------------------------- INPUT
String input = JOptionPane.showInputDialog
("Enter name (like your university)");
// --------------------------------------------------------- PROCESSING
char result = input.charAt(i);
do{
if (vowels.contains(result))
vnum++;
if (cons.contains(result))
cnum++;
if (!input.matches(("[a-zA-Z]+")))
snum++;
i++;
}while (i < input.length());
System.out.println("There are " + vnum + " vowels, " + cnum + " consonants, and " + snum + "spaces");
您不会在中找到char
一个Set<String>
。
在循环中,您要递增i
而不选择相应的字符。
您不必要地(并且不正确地)使用了正则表达式,而简单的表达式else
就足够了。
试试这个:
private static final Set<Character>
vowels = new HashSet<>
(Arrays.asList('a','e','i','o','u','y'));
private static final Set<Character>
cons = new HashSet<>
(Arrays.asList('b','c','d','f','g','h','j','k','l','m','n','p','q','r','s','t','v','w','x','z'));
...
for (int i = 0; i < input.length(); i++) {
Character result = input.charAt(i);
if (vowels.contains(result))
vnum++;
else if (cons.contains(result))
cnum++;
else
snum++;
}
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