output.txt
1.1.1.1:22/ does not support password authentication. [ERROR] target ssh://2.2.2.2:22/ does not support password authentication. [ERROR] target ssh://3.3.3.3
我想删除字符串:22/ does not support password authentication. [ERROR] target ssh://从output.txt，并把IP地址在新文件
所需的输出：
1.1.1.1
2.2.2.2
3.3.3.3
我尝试过
cat output.txt | grep -vE "(:22/ does not support password authentication. [ERROR] target ssh://)
和
cat output.txt | egrep -v ":22/ does not support password authentication. [ERROR] target ssh://"
和cat output.txt | grep -v ":22/ does not support password authentication. [ERROR] target ssh://"而上述3个命令不删除什么。尝试使用awk-相同的结果：
awk '{gsub(":22/ does not support password authentication. [ERROR] target ssh://","");print}' output.txt
我没有尝试，sed因为我的字符串包含转义字符
这是完成此工作的perl一线客：
perl -ape 's/.*?(\d+(?:\.\d+){3})/$1\n/g' file.txt
1.1.1.1
2.2.2.2
3.3.3.3
解释：
s/ # substitute
.*? # 0 or more any character but newline
( # start group 1
\d+ # 1 or more digits
(?: # start non capture group
\. # a dot
\d+ # 1 or more digits
){3} # end group, must appear 3 times
) # end group 1
/ # with
$1\n # content of group 1 (i.e. the IP), followed by linefeed
/g # global
如果只想匹配IP地址，则必须\d+将上述正则表达式中所有出现的内容替换为：
(?:25[0-5]|2[0-4]\d|[01]\d?\d?)
给出：
s/.*?((?:25[0-5]|2[0-4]\d|[01]\d?\d?)(?:\.(?:25[0-5]|2[0-4]\d|[01]\d?\d?)){3})/$1\n/g
本文收集自互联网，转载请注明来源。
如有侵权，请联系 [email protected] 删除。
我来说两句