我正在做关于模板的作业,并从文件中读取。我有一个名为“ Cfile”的模板类和一个“学生”类。我将相关代码放在这里,然后询问错误:
#include<iostream>
#include<fstream>
using namespace std;
template <class T>
class Cfile
{
ifstream fileIn;
...jump down a bit
T read()
{
return T(this->fileIn); //the error is in this line
}
我得到了错误:cannot convert from 'std::ifstream' to 'char*'
在返回线上。
当然,“学生”课程的C'tor会获得ifstream& in
并创建一个新的“学生”:
Student::Student(ifstream & in)
{
in.read((char*)&age, sizeof(age));
}
编辑:我想我明白现在出了什么问题。我还有一个名为“ MyString”的类,它具有以下读取方法:
char* read(ifstream& in);
所以也许我不小心覆盖了read方法?但是返回类型不同,因此不应发生。
编辑2:main.cpp-
#include"Cfile.h"
#include"Student.h"
#include"Queue.h"
#include "C.h"
int main()
{
ifstream i;
i.open("strings.txt");
Cfile<Student>stuFile("strings.txt");
Student a, b, c;
a.age = 10;
b.age = 20;
c.age = 30;
stuFile.write(a);
stuFile.write(b);
stuFile.write(c);
Student d = Student(i);
Student e = Student(i);
Student f = Student(i);
Cfile<char*> st;
Queue<char*> st1;
for (int i = 0;i < 10;i++)
{
st.read(st1.arr, 10);
}
i.close();
return 0;
}
MyString.cpp-
#include "MyString.h"
MyString::MyString()
{
}
MyString::MyString(char * st)
{
this->st = st;
}
char * MyString::read(ifstream& in)
{
in.read(this->st, sizeof(st));
return st;
}
const char * MyString::getStr()
{
return this->st;
}
MyString::~MyString()
{
}
Student.cpp-
#include "Student.h"
/*bool Student::operator==(Student student)
{
return this->name == student.name &&
this->lastName == student.lastName &&
this->age == student.age;
}*/
Student::Student()
{
}
Student Student::read(ifstream& in)
{
in.read((char*)&age, sizeof(age));
return *this;
}
void Student::write(ofstream & out)
{
out.write((char*)&age, sizeof(age));
}
Student::Student(ifstream & in)
{
in.read((char*)&age, sizeof(age));
}
Student::Student(Student &s)
{
this->age = s.age;
}
Student::Student(int age)
{
//Student s = new Student;
this->age = age;
}
Student::~Student()
{
}
Cfile.h-
#pragma once
#include<iostream>
#include<fstream>
using namespace std;
template <class T>
class Cfile
{
ifstream fileIn;
ofstream fileOut;
public:
Cfile() {};
Cfile(char* _fileName) {
fileIn.open(_fileName, ios::binary);
fileOut.open(_fileName, ios::binary);
}
int read(T **apBuf, int aNum)
{
int count=0;
apBuf = new T*[aNum];
for (int i = 0;i < aNum;i++)
{
*apBuf[i] = this->read();
count++;
}
return count;
}
void write(T &t)
{
t.write(this->fileOut);
}
void write(T* apBuf, int aNum) {
for (int i = 0;i < aNum;i++)
{
write(apBuf[i]);
}
}
int size()
{
fileIn.seekg(0, ios::end);
return (fileIn.tellg() / sizeof(T));
}
T read()
{
return T(this->fileIn);
}
~Cfile() {};
};
考虑到问题的质量,我将尽力回答。
Cfile<char*> st;
Queue<char*> st1;
for (int i = 0;i < 10;i++)
{
st.read(st1.arr, 10); // Error happens here
}
i.close();
反过来在这里失败
int read(T **apBuf, int aNum)
{
int count=0;
apBuf = new T*[aNum];
for (int i = 0;i < aNum;i++)
{
*apBuf[i] = this->read(); // Error
count++;
}
return count;
}
您正在尝试从中构建char *
出一个ifstream
,但失败的原因是,这是非常不同的类型。我建议您重新考虑标线。我还怀疑您不确定确切的含义ifstream
,因此建议您重新阅读文档。
在侧节点上,您对new
on的调用apBuf = new T*[aNum];
不会delete
事先调用,这意味着您存在内存泄漏
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