在Access DB中将字段拆分为多个记录

悖论

我有一个MS Access数据库,其中有一个名为的字段Field1,其中包含多个用逗号分隔的值。IE,

Value1,Value 2, Value3, Value 4,Value5

我试图将值拆分成单独的字段,而不是将其拆分为单独的字段,而是将记录复制并存储在另一个字段中。这样,包含一个具有三个值的单元格的记录将被重复三次,每个记录的新字段中所包含的值都不同。例如,

在查询/运行模块之前:

+-----------+------------------------+ | App Code | Field1 | +-----------+------------------------+ | AB23 | Value1, Value 2,Value3 | +------------------------------------+

在查询/运行模块之后:

+-----------------------------------------------+ | App Code | Field1 | Field2 | +-----------+------------------------+----------+ | AB23 | Value1, Value 2,Value3 | Value1 | +-----------+------------------------|----------+ | AB23 | Value1, Value 2,Value3 | Value 2 | +-----------+------------------------+----------+ | AB23 | Value1, Value 2,Value3 | Value3 | +-----------+------------------------+----------+

到目前为止,我发现了几个有关将一个字段拆分 两个甚至几个不同字段的问题,但是我还没有找到任何将记录垂直拆分的解决方案。在这些解决方案中,一些使用查询,其他使用模块,但是我也不确定哪种方法最有效,因此我决定使用VBA模块。

因此,这是迄今为止我发现最有用的VBA模块:

Function CountCSWords (ByVal S) As Integer
      ' Counts the words in a string that are separated by commas.

      Dim WC As Integer, Pos As Integer
         If VarType(S) <> 8 Or Len(S) = 0 Then
           CountCSWords = 0
           Exit Function
         End If
         WC = 1
         Pos = InStr(S, ",")
         Do While Pos > 0
           WC = WC + 1
           Pos = InStr(Pos + 1, S, ",")
         Loop
         CountCSWords = WC
      End Function

      Function GetCSWord (ByVal S, Indx As Integer)
      ' Returns the nth word in a specific field.

      Dim WC As Integer, Count As Integer, SPos As Integer, EPos As Integer
         WC = CountCSWords(S)
         If Indx < 1 Or Indx > WC Then
           GetCSWord = Null
           Exit Function
         End If
         Count = 1
         SPos = 1
         For Count = 2 To Indx
           SPos = InStr(SPos, S, ",") + 1
         Next Count
         EPos = InStr(SPos, S, ",") - 1
         If EPos <= 0 Then EPos = Len(S)
         GetCSWord = Trim(Mid(S, SPos, EPos - SPos + 1))
      End Function

但是,如何在访问查询中使用它来实现上述预期结果?否则,除了查询(即仅使用VBA模块)以外,还有没有更好的方法可以得出相同的结论?

编辑

请注意,表中的主键Application Code不是自动编号。这个主键是文本的,并且是独特的。为了拆分记录,这将需要复制主键,这很好。

dbmitch

这是在Table1中使用Field1,Field2的示例代码片段

Option Explicit

Public Sub ReformatTable()

    Dim db          As DAO.Database
    Dim rs          As DAO.Recordset
    Dim rsADD       As DAO.Recordset

    Dim strSQL      As String
    Dim strField1   As String
    Dim strField2   As String
    Dim varData     As Variant
    Dim i           As Integer

    Set db = CurrentDb

    ' Select all eligible fields (have a comma) and unprocessed (Field2 is Null)
    strSQL = "SELECT Field1, Field2 FROM Table1 WHERE ([Field1] Like ""*,*"") AND ([Field2] Is Null)"

    Set rsADD = db.OpenRecordset("Table1", dbOpenDynaset, dbAppendOnly)

    Set rs = db.OpenRecordset(strSQL, dbOpenDynaset)
    With rs
        While Not .EOF
            strField1 = !Field1
            varData = Split(strField1, ",") ' Get all comma delimited fields

            ' Update First Record
            .Edit
            !Field2 = Trim(varData(0)) ' remove spaces before writing new fields
            .Update

            ' Add records with same first field 
            ' and new fields for remaining data at end of string
            For i = 1 To UBound(varData)
                With rsADD
                    .AddNew
                    !Field1 = strField1
                    !Field2 = Trim(varData(i)) ' remove spaces before writing new fields
                    .Update
                End With
            Next
            .MoveNext
        Wend

        .Close
        rsADD.Close

    End With

    Set rsADD = Nothing
    Set rs = Nothing
    db.Close
    Set db = Nothing

End Sub

之前的示例

运行程序后

编辑

更新示例以生成新的主键

如果必须基于先前的Appcode生成新的AppCode(并且将AppCode假定为文本字段),则可以使用此示例根据最后的Appcode生成唯一的主键。

Option Explicit

Public Sub ReformatTable()

    Dim db          As DAO.Database
    Dim rs          As DAO.Recordset
    Dim rsADD       As DAO.Recordset

    Dim strSQL      As String
    Dim strField1   As String
    Dim strField2   As String
    Dim varData     As Variant
    Dim strAppCode  As String
    Dim i           As Integer

    Set db = CurrentDb

    ' Select all eligible fields (have a comma) and unprocessed (Field2 is Null)
    strSQL = "SELECT AppCode, Field1, Field2 FROM Table1 WHERE ([Field1] Like ""*,*"") AND ([Field2] Is Null)"

    ' This recordset is only used to Append New Records
    Set rsADD = db.OpenRecordset("Table1", dbOpenDynaset, dbAppendOnly)

    Set rs = db.OpenRecordset(strSQL, dbOpenDynaset)
    With rs
        While Not .EOF

            ' Do we need this for newly appended records?
            strAppCode = !AppCode

            strField1 = !Field1
            varData = Split(strField1, ",") ' Get all comma delimited fields

            ' Update First Field
            .Edit
            !Field2 = Trim(varData(0)) ' remove spaces before writing new fields
            .Update

            ' Add new fields for remaining data at end of string
            For i = 1 To UBound(varData)
                With rsADD

                    .AddNew

                    ' ***If you need a NEW Primary Key based on current AppCode
                    !AppCode = strAppCode & "-" & i

                    ' ***If you remove the Unique/PrimaryKey and just want the same code copied
                    !AppCode = strAppCode

                    ' Copy previous Field 1
                    !Field1 = strField1

                    ' Insert Field 2 based on extracted data from Field 1
                    !Field2 = Trim(varData(i)) ' remove spaces before writing new fields
                    .Update
                End With
            Next
            .MoveNext
        Wend

        .Close
        rsADD.Close

    End With

    Set rsADD = Nothing
    Set rs = Nothing
    db.Close
    Set db = Nothing

End Sub

运行代码后新的AppCode密钥的示例

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