我有这个结构:
struct ChangeIntItem
{
char *unit;
const char **parser;
int *changevalue;
uint16_t *change_eeprom_value;
int maximum;
int minimum;
};
我想使用此struct-Variable初始化其他变量:
struct ChangeIntItem ChangeIntItemTypeBoolean = { .unit = "", .minimum = 0, .maximum = 1, .parser = {"off", "on"}};
它工作正常,但我收到一些警告:
Severity Code Description Project File Line
Warning braces around scalar initializer Handsteuerung C:\Users\... 11
Severity Code Description Project File Line
Warning (near initialization for 'ChangeIntItemTypeBoolean.parser') Handsteuerung C:\Users\... 11
Severity Code Description Project File Line
Warning initialization from incompatible pointer type Handsteuerung C:\Users\... 11
Severity Code Description Project File Line
Warning (near initialization for 'ChangeIntItemTypeBoolean.parser') Handsteuerung C:\Users\... 11
Severity Code Description Project File Line
Warning excess elements in scalar initializer Handsteuerung C:\Users\... 11
Severity Code Description Project File Line
Warning (near initialization for 'ChangeIntItemTypeBoolean.parser') Handsteuerung C:\Users\... 11
在另一种情况下,我编写了一个函数,将结构的变量设置为默认值,但我更喜欢这种方法,因为它的时间要短得多。
所有由'.parser = {“ off”,“ on”}'引起的错误,但我没有发现我的错误...
您可以使用复合文字,因此将init更改为
struct ChangeIntItem ChangeIntItemTypeBoolean = { .unit = "", .minimum = 0, .maximum = 1, .parser = (const char *[]){"off", "on"}};
测试
#include <stdio.h>
#include <stdint.h>
struct ChangeIntItem
{
char *unit;
const char **parser;
int *changevalue;
uint16_t *change_eeprom_value;
int maximum;
int minimum;
};
int main()
{
struct ChangeIntItem ChangeIntItemTypeBoolean = { .unit = "", .minimum = 0, .maximum = 1, .parser = (const char *[]){"off", "on"}};
printf ("%s - %s\n", ChangeIntItemTypeBoolean.parser[0], ChangeIntItemTypeBoolean.parser[1]);
}
输出
off - on
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