如何将Objective-C块转换为Swift闭包？

Graeme 发表于 Dev

格莱美

我有下面的Github dzenbot / DZNPhotoPickerController的Objective-C块分配示例，我正努力将其转换为Swift。控制器是一个UIImagePickerController。

controller.finalizationBlock = ^(UIImagePickerController *picker, NSDictionary *info) {

    UIImage *image = info[UIImagePickerControllerEditedImage];
    weakSelf.imageView.image = image;

    // Dismiss when the crop mode was disabled
    if (picker.cropMode == DZNPhotoEditorViewControllerCropModeNone) {
        [weakSelf dismissController:picker];
    }
};

我已经尝试了以下方法，但是无法弄清楚我要去哪里。

controller.finalizationBlock = { (picker: UIImagePickerController, info: NSDictionary) -> UIImagePickerControllerFinalizationBlock! in
        var image = UIImagePickerControllerEditedImage(info)
        imageView.image = image

        // Dismiss when the crop mode was disabled
        if (picker.cropMode == .None) {
            dismissEditor(picker)
        }
    }

我得到的错误是：

“无法分配类型'（UIImagePickerController，NSDictionary）-> UIImagePickerControllerFinalizationBlock的值！键入“ UIImagePickerControllerFinalizationBlock！”

泽蒙

Objective-C块不返回任何内容，因此对它的关闭应如下所示：

controller.finalizationBlock = { (picker, info) in
        var image = UIImagePickerControllerEditedImage(info)
        imageView.image = image

        // Dismiss when the crop mode was disabled
        if (picker.cropMode == .None) {
            dismissEditor(picker)
        }
    }

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