不确定如何从函数返回值

基蒂斯通

我有一个代码，我需要返回值，但是我认为我无法return正确放置该语句。我需要将IP地址的组合列表返回给python中的调用函数

def call_me ():
  ACCESS_KEY= "XX"
  SECRET_KEY= "XXXX"
  regions = ['us-west-2','eu-central-1','ap-southeast-1']
  for region in regions:
    instance_information = {}
    ip_dict = {}
    client = boto3.client('ec2',aws_access_key_id=ACCESS_KEY,aws_secret_access_key=SECRET_KEY,region_name=region,)
    addresses_dict = client.describe_addresses().get('Addresses')

    for address in addresses_dict:

        if address.get('InstanceId'):
            instance_information[address['InstanceId']] = [address.get('PublicIp')]
         #   print  instance_information

    dex_dict = client.describe_tags().get('Tags')
    for dex in dex_dict:
        if instance_information.get(dex['ResourceId']):
            instance_information[dex['ResourceId']].append(dex.get('Value'))
    for instance in instance_information:

        if len(instance_information[instance]) == 2:
            ip_dict[instance_information[instance][0]] = instance_information[instance][1]
        else:
            ip_dict[instance_information[instance][0]] = ''
#    print (json.dumps(instance_information,indent=4))
    #print type(instance_information)
    ip_list = [i[0]  for i in instance_information.values()]
    print (ip_list)

现在我不确定在哪里放置该return ip_list语句，因为该语句在3个区域中运行

摩西·科莱多耶（Moses Koledoye）

您可以ip_list在for循环之前定义循环，extend并使用每个区域的值列表进行定义：

ip_list = []
for region in regions:
    instance_information = {}
    #
    # your code
    #
    ip_list.extend(i[0]  for i in instance_information.values())
    print(ip_list)
return ip_list

如果要将列表中区域中的值保留在列表中，则可以将扩展行替换为： ip_list.append([i[0] for i in instance_information.values()])

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