无法解析名称为Y的servlet中名称为X的视图

我正在将Spring和AngularJS用于其余的Web应用程序。基于本教程，并基于本教程，我创建了以下文件夹结构：

-src
|----main
    |----webapp
        |----static
            |----api
            |----assets
            |----resources
            |----sections
            |----services
            |----index.html
        |----WEB-INF
            |----web.xml
            |----spring
                |----dispatcher-servlet.xml
                |----applicationContext.xml

我想提供静态HTML文件，因此我将资源声明如下：

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd">

<mvc:annotation-driven></mvc:annotation-driven>
<context:component-scan base-package="org.tools.mvc.controllers"></context:component-scan>
<mvc:resources location="/static/" mapping="/**"/>
<mvc:resources location="/static/api/" mapping="/api/**"/>
<mvc:resources location="/static/assets/" mapping="/assets/**"/>
<mvc:resources location="/static/resources/" mapping="/resources/**"/>
<mvc:resources location="/static/services/" mapping="/services/**"/>
<mvc:resources location="/static/sections/home/" mapping="/sections/home/**"/>


<bean name="viewResolver" class="org.springframework.web.servlet.view.BeanNameViewResolver"></bean>
<bean name="jsonTemplate" class="org.springframework.web.servlet.view.json.MappingJackson2JsonView"></bean>

我的问题是，当我部署应用程序（我正在使用Glassfish服务器）时，会发生以下错误（在Eclipse控制台以及浏览器页面中）：

2016-05-27T04:46:06.640-0700|Warning: StandardWrapperValve[dispatcher]: Servlet.service() for servlet dispatcher threw exception
javax.servlet.ServletException: Could not resolve view with name 'index.html' in servlet with name 'dispatcher'

该服务的功能不受影响（使用Postman测试其余api成功）。到目前为止，为了进一步开发该应用程序，我手动将index.html添加到URL的末尾（例如localhost：8080 / status / index.html）。在Web Deployment Assembly中声明的“ /”的来源是：

来源：/ src / main / webapp

部署路径：/

更新：web.xml文件如下所示：

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" version="3.1">
<display-name>status</display-name>

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/spring/applicationContext.xml</param-value>
</context-param>

<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/dispatcher-servlet.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

如何解决此错误？

谢谢

PS在SO上找到的解决方案不适用于我的方案。