嗨,我是RXJava的新手,我正在尝试处理我的第一个RxJava示例,如下所示
Observable<String> myObservable = Observable.create(
new Observable.OnSubscribe<String>() {
public void call(Subscriber<? super String> subscriber) {
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
subscriber.onNext("hello world");
subscriber.onCompleted();
}
}
).subscribeOn(Schedulers.computation());
Observable<String> myObservable1 = Observable.just("thank you");
Observable observable3 = Observable.zip(myObservable, myObservable1, new Func2<String,String,String>() {
@Override
public String call(String o, String o2) {
return o+":"+o2;
}
});
observable3.subscribe(new Action1<String>() {
@Override
public void call(String o) {
System.out.println("before");
System.out.println(o);
}
});
System.out.println("after");
我想打印before
然后after
,如何在不带rxjava的情况下进行打印sleep
一种可能的方式:
Observable<String> myObservable = Observable.create(
new Observable.OnSubscribe<String>() {
public void call(Subscriber<? super String> subscriber) {
subscriber.onNext("hello world");
subscriber.onCompleted();
}
}
).subscribeOn(Schedulers.computation());
Observable<String> myObservable1 = Observable.just("thank you");
Observable observable3 = Observable.zip(myObservable, myObservable1, new Func2<String,String,String>() {
@Override
public String call(String o, String o2) {
return o+":"+o2;
}
});
Observable.just("before").concatWith(observable3).concatWith(Observable.just("after")).toBlocking().subscribe(new Action1<String>() {
@Override
public void call(String s) {
System.out.println(s);
}
});
结果是:
之前
你好世界:谢谢你
之后
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