我正在尝试使用正则表达式快速替换匹配的字符串，我的要求如下
originalString = "It is live now at Germany(DE)"
我希望(" ")ie中的字符串DE以空格分隔，即“ D E”
所以replaceString应该是"It is live now at Germany(D E)"
我尝试下面的代码
var value: NSMutableString = "It is live now at Germany(DE)"
let pattern = "(\\([A-Za-z ]+\\))"
let regex = try? NSRegularExpression(pattern: pattern)
regex?.replaceMatches(in: value, options: .reportProgress, range:
NSRange(location: 0,length: value.length), withTemplate: " $1 ")
print(value)
输出是It is live now at Germany (DE)，我知道这不是必需的。这里是基于模板的，我们无法根据匹配的字符串值进行修改。有什么办法可以做到这一点？
提前致谢
您可以使用
var value: NSMutableString = "It is live now at Germany(DE) or (SOFE)"
let pattern = "(?<=\\G(?<!\\A)|\\()[A-Za-z](?=[A-Za-z]+\\))"
let regex = try? NSRegularExpression(pattern: pattern)
regex?.replaceMatches(in: value, options: .reportProgress, range: NSRange(location: 0,length: value.length), withTemplate: "$0 ")
print(value)
要不就
let val = "It is live now at Germany(DE) or (SOFE)"
let pattern = "(?<=\\G(?<!\\A)|\\()[A-Za-z](?=[A-Za-z]+\\))"
print( val.replacingOccurrences(of: pattern, with: "$0 ", options: .regularExpression, range: nil) )
输出： It is live now at Germany(D E) or (S O F E)
图案细节
(?<=\\G(?<!\\A)|\\()-(与前面成功匹配之后或结尾位置匹配的正向后看[A-Za-z] -匹配并使用任何ASCII字母(?=[A-Za-z]+\\))-与位置相匹配的正向超前查询，后跟1+ ASCII字母和一个)字符。将$0在更换插入整场比赛值回生成的字符串。
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我来说两句