我想从此obj中合并对象:
objs = {
one: { description: "value", amount: 5, value: { description: "value desc", identifier: "some text"} },
two: { description: "value", amount: 5, value: { description: "value desc", identifier: "some text"} }
}
到这个obj:
objs = {
one: { original_description: "value", amount: 5, description: "value desc", identifier: "some text" },
two: { original_description: "value", amount: 5, description: "value desc", identifier: "some text" }
}
UPD: @ryeballar的解决方案正在运行,但是我发现了问题,“子对象”包含与父对象相同的键名。
您可以使用mapValues(),并具有一个回调,该回调value
通过使用omit()并将其自身合并()将返回的对象省略value
。
var objs = {
one: { description: "value", amount: 5, value: { identifier : "some text"} },
two: { description: "value", amount: 5, value: { identifier : "some text"} }
};
var result = _.mapValues(objs, i => _(i).omit('value').merge(i.value).value());
document.write('<pre>' + JSON.stringify(result, 0, 4) + '</pre>');
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.11.2/lodash.js"></script>
更新
为了响应您的更新,您仍然可以使用上面的原始解决方案,并进行一些调整,使用mapKeys()从给定前缀中转换每个对象键(如果它来自合并源)。
var objs = {
one: { description: "value", amount: 5, value: { description: "value desc", identifier: "some text"} },
two: { description: "value", amount: 5, value: { description: "value desc", identifier: "some text"} },
three: { description: "value", amount: 5, value: null },
four: { description: "value", amount: 5 }
}
function mergeFromKey(object, mergeKey, prefix) {
return _.mapValues(object, item =>
_(item).mapKeys((v, k) => (_.get(item[mergeKey], k)? prefix: '') + k)
.omit(mergeKey)
.merge(item[mergeKey])
.value()
);
}
var result = mergeFromKey(objs, 'value', 'original_');
document.write('<pre>' + JSON.stringify(result, 0, 4) + '</pre>');
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.11.2/lodash.js"></script>
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