查找最小值并将其以相同顺序分配给新变量-C ++

让我们将问题分为几个部分：a）找到最小的x值b）建立后，您以模量向量的大小运行向量中的位置

代码：（并不太强调适当的样式）

vector<pair<double, double>> vec = { {319.402,213.309} ,{184.437,312.164 },{54.9806,183.36} ,{187.458,95.2848} }
, vec2;

double minX = vec[0].first;
int minIndx = 0;
for (int i = 1; i < static_cast<int>(vec.size()); i++)
    if (vec[i].first < minX)
    {
        minIndx = i; //saves the index
        minX = vec[i].first; //saves the minX value
    }

vec2.emplace_back(vec[minIndx]); //put it in the result vector (vec2)


//emplace everything else to the result vector modulu vec.size()
for (int i = minIndx + 1; i != minIndx; i = (i + 1) % static_cast<int>(vec.size()))
    vec2.emplace_back(vec[i]);

//prints the result
for (const auto &v: vec2)
    cout << "(" <<v.first << ", " <<v.second << ")\n";