我创建了一个带有带有arrayadapter的listview的应用程序,用户可以动态填充该应用程序。我将输入的信息作为json字符串存储在首选项中,并在刷新应用程序时获得包含条目的列表。问题是,我希望网络操作后每个条目旁边的图像发生变化。我面临的问题似乎是由于列表中的元素是动态添加的,因此我似乎没有找到一种好的方法来更新onPostExecute()方法上的imageview,也不能专门针对每个条目,因为它们共享相同的布局ID。
这是我的适配器内部的getView()方法:
@Override
public View getView(int position, View convertView, ViewGroup parent) {
ViewHolder holder = null;
if (convertView == null) {
LayoutInflater inflater = (LayoutInflater) context
.getSystemService(Activity.LAYOUT_INFLATER_SERVICE);
convertView = inflater.inflate(R.layout.product_list_item, null);
holder = new ViewHolder();
holder.deviceName = (TextView) convertView
.findViewById(R.id.txt_pc_name);
holder.deviceIp = (TextView) convertView
.findViewById(R.id.txt_pdt_desc);
holder.devicePort = (TextView) convertView
.findViewById(R.id.txt_pdt_price);
holder.favoriteImg = (ImageView) convertView
.findViewById(R.id.imgbtn_favorite);
convertView.setTag(holder);
} else {
holder = (ViewHolder) convertView.getTag();
}
Devices device = (Devices) getItem(position);
holder.deviceName.setText(device.getName());
holder.deviceIp.setText(device.getIpOnline());
holder.devicePort.setText(device.getPortOnline() + "");
return convertView;
}
这是我的AsyncTask:
public class Connection extends AsyncTask<String, Void, String> {
private String ipOnline;
private int portOnline;
private String ipWol;
private int portWol;
private String macAddress;
private ImageView img;
private Context context;
public interface AsyncResponse {
void processFinish(String output);
}
public AsyncResponse delegate = null;
public Connection(Context mContext, ImageView Img,String IpOnline, int PortOnline, String IpWol, int PortWol, String MacAddress, AsyncResponse delegate) {
ipOnline = IpOnline;
portOnline = PortOnline;
ipWol = IpWol;
portWol = PortWol;
macAddress = MacAddress;
context = mContext;
// inflate = Inflate;
img = Img;
// spin = spinner;
this.delegate = delegate;
}
public int status;
@Override
protected String doInBackground(String... arg0) {PreferenceManager.getDefaultSharedPreferences(lastContext);
try {
Socket echoSocket = new Socket();
echoSocket.connect(new InetSocketAddress(ipOnline,portOnline),2000);
if(echoSocket.isConnected())
status = 1;
} catch (Exception e) {
status = 0;
}
if(status == 0)
return "0";
else
return "1";
}
@Override
protected void onProgressUpdate(Void... values) {}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
ImageView img = (ImageView) activity.findViewById(R.id.imgbtn_favorite);
if (status == 0)
img.setImageResource(android.R.drawable.presence_offline);
else
img.setImageResource(android.R.drawable.presence_online);
delegate.processFinish(result);
}
}
这是我的电话:
new Connection(activity, img, product.getIpOnline(), Integer.parseInt(product.getPortOnline()), product.getIpWol(), Integer.parseInt(product.getPortWol()), product.getMacAddress(), new Connection.AsyncResponse() {
@Override
public void processFinish(String output) {
}
}).execute();
我想出了一个解决方案。
我在适配器上创建了一个公共变量,并添加了所有图像:
public List<ImageView> allImages = new ArrayList<ImageView>();
public List<ImageView> getAllImages(){
return this.allImages;
}
this.allImages.add((ImageView) convertView
.findViewById(R.id.imgbtn_favorite));
然后在我的零散活动onCreateView方法上,我部署了一个延迟的可运行对象:
(new Handler()).postDelayed(new Runnable() {
@Override
public void run() {
updateStatus();
}
}, 500);
updateStatus()方法将初始化images变量,并开始网络检查以确定要使用的图像。然后将其相应地应用。
public void updateStatus() {
List<ImageView> images = deviceListAdapter.getAllImages();
if(count > 0 && images.size() > 0) {
for (int i = 0; i < deviceListAdapter.getCount() ; i++) {
Devices product = (Devices) deviceListAdapter.getItem(i);
if((TextUtils.isDigitsOnly(product.getPortOnline()) && TextUtils.isDigitsOnly(product.getPortWol())) && (!product.getPortOnline().isEmpty() && !product.getPortWol().isEmpty())) {
new Connection(activity, images.get(i), product.getIpOnline(), Integer.parseInt(product.getPortOnline()), product.getIpWol(), Integer.parseInt(product.getPortWol()), product.getMacAddress(), new Connection.AsyncResponse() {
@Override
public void processFinish(Boolean output) {
}
}).execute();
}
}
}
}
这可能不是最佳选择,但可以随时添加更好的解决方案。
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