杰克逊日期格式问题:Java bean到JSON字符串转换

拉胡尔·米塔尔

我正在使用Jackson 2.7.4版本将Java bean转换为JSON字符串。这样做时,我面临日期格式问题。使用的是Java 1.7版本。

豆角,扁豆 :

public class BaseBean {

    private java.util.Date fromDate;

    public Date getFromDate() {
        return fromDate;
    }

    public void setFromDate(Date fromDate) {
        this.fromDate = fromDate;
    }
}

越来越低于日期格式

{"fromDate":1465370289436}

我不需要的。然后我配置下面的代码

ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(com.fasterxml.jackson.databind.SerializationFeature.WRITE_DATES_AS_TIMESTAMPS , false);
jsonInString = objectMapper.writeValueAsString(objJava);

然后我得到JSON以下日期格式:

{"fromDate":"2016-06-08T07:47:06.636+0000"}

预期的日期格式:

{"fromDate":{"date":8,"day":3,"hours":12,"minutes":48,"month":5,"seconds":9,"time":1465370289436,"timezoneOffset":-330,"year":116}}

是否有任何配置可以处理它并获得JSON字符串中的预期日期格式。

桑托什

JSON日期序列化器:

public class CustomDateSerializer extends JsonSerializer<Date> {

@Override
public void serialize(Date date, JsonGenerator jgen, SerializerProvider provider) throws IOException,
        JsonProcessingException {

    // below methods of Date object is deprecated - consider this as sample example 
    int idate = date.getDate();
    int day = date.getDay();
    int hours = date.getHours();
    int minutes = date.getMinutes();
    int month = date.getMonth();
    int seconds = date.getSeconds();
    long time = date.getTime();
    int timezoneOffset = date.getTimezoneOffset();
    int year = date.getYear();

    jgen.writeStartObject();

    jgen.writeNumberField("date", idate);
    jgen.writeNumberField("day", day);
    jgen.writeNumberField("hours", hours);
    jgen.writeNumberField("minutes", minutes);
    jgen.writeNumberField("month", month);
    jgen.writeNumberField("seconds", seconds);
    jgen.writeNumberField("time", time);
    jgen.writeNumberField("timezoneOffset", timezoneOffset);
    jgen.writeNumberField("year", year);

    jgen.writeEndObject();      
}

@Override
public Class<Date> handledType() {
    return Date.class;
}

}

在SimpleModule中设置序列化器:

ObjectMapper objectMapper = new ObjectMapper();
    String jsonInString = "";
    try {
        SimpleModule myModule = new SimpleModule();

        myModule.addSerializer(Date.class, new CustomDateSerializer());
        objectMapper.registerModule(myModule);
        jsonInString = objectMapper.writerWithDefaultPrettyPrinter().writeValueAsString(objJava);
    } catch (JsonProcessingException e1) {          
        e1.printStackTrace();
    }

希望这会有所帮助!

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