第一次海报在这里。我现在正在学校里上C语言编程课程，过去只学过编程要点。我一直在努力，但是以某种方式设法解决了直到第5周的所有问题。
基本上，这就是我到目前为止所拥有的。我正在尝试做的是让该程序循环运行一次，然后将其循环回到菜单选择屏幕。我相信我需要将所有内容放入while循环中，但是我尝试将其添加进去，但是所有发生的事情是我最终看到了该程序，要求我输入已经选择的小时数。如果有帮助，我正在使用Microsoft Visual Studio Express 2015。
感谢您的帮助/解释。
#include <stdio.h>
#include <iostream>
#define BASEPAY1 8.75
#define BASEPAY2 9.33
#define BASEPAY3 10
#define BASEPAY4 11.20
#define BASEHRS 40
#define OVERTIME 1.5
#define AMT1 300
#define AMT2 150
#define RATE1 0.15
#define RATE2 0.20
#define RATE3 0.25
int main(void)
{
int hours;
float gross;
float net;
float taxes;
int choice;
printf("\n\nMenu\n----------\n\n");
printf("1) $8.75/hr\n");
printf("2) $9.33/hr\n");
printf("3) $10.00/hr\n");
printf("4) $11.20/hr\n");
printf("5) quit\n\n");
printf("Enter the number that corresponds to your rate or press 5 to quit.\n");
scanf_s("%d", &choice);
switch (choice) {
case 1:
printf("Enter the number of hours worked this week: \n");
scanf_s("%d", &hours);
if (hours <= BASEHRS)
gross = hours * BASEPAY1;
else
gross = BASEHRS * BASEPAY1 + (hours - BASEHRS) * BASEPAY1 * OVERTIME;
if (gross <= AMT1)
taxes = gross * RATE1;
else if (gross <= AMT1 + AMT2)
taxes = AMT1 * RATE1 + (gross - AMT1) * RATE2;
else
taxes = AMT1 * RATE1 + AMT2 * RATE2 + (gross - AMT1 - AMT2) * RATE3;
net = gross - taxes;
printf("gross: $%.2f \n", gross);
printf("taxes: $%.2f \n", taxes);
printf("net: $%.2f \n", net);
break;
case 2:
printf("Enter the number of hours worked this week: ");
scanf_s("%d", &hours);
if (hours <= BASEHRS)
gross = hours * BASEPAY2;
else
gross = BASEHRS * BASEPAY2 + (hours - BASEHRS) * BASEPAY2 * OVERTIME;
if (gross <= AMT1)
taxes = gross * RATE1;
else if (gross <= AMT1 + AMT2)
taxes = AMT1 * RATE1 + (gross - AMT1) * RATE2;
else
taxes = AMT1 * RATE1 + AMT2 * RATE2 + (gross - AMT1 - AMT2) * RATE3;
net = gross - taxes;
printf("gross: $%.2f \n", gross);
printf("taxes: $%.2f \n", taxes);
printf("net: $%.2f \n", net);
break;
case 3:
printf("Enter the number of hours worked this week: ");
scanf_s("%d", &hours);
if (hours <= BASEHRS)
gross = hours * BASEPAY3;
else
gross = BASEHRS * BASEPAY3 + (hours - BASEHRS) * BASEPAY3 * OVERTIME;
if (gross <= AMT1)
taxes = gross * RATE1;
else if (gross <= AMT1 + AMT2)
taxes = AMT1 * RATE1 + (gross - AMT1) * RATE2;
else
taxes = AMT1 * RATE1 + AMT2 * RATE2 + (gross - AMT1 - AMT2) * RATE3;
net = gross - taxes;
printf("gross: $%.2f \n", gross);
printf("taxes: $%.2f \n", taxes);
printf("net: $%.2f \n", net);
break;
case 4:
printf("Enter the number of hours worked this week: ");
scanf_s("%d", &hours);
if (hours <= BASEHRS)
gross = hours * BASEPAY4;
else
gross = BASEHRS * BASEPAY4 + (hours - BASEHRS) * BASEPAY4 * OVERTIME;
if (gross <= AMT1)
taxes = gross * RATE1;
else if (gross <= AMT1 + AMT2)
taxes = AMT1 * RATE1 + (gross - AMT1) * RATE2;
else
taxes = AMT1 * RATE1 + AMT2 * RATE2 + (gross - AMT1 - AMT2) * RATE3;
net = gross - taxes;
printf("gross: $%.2f \n", gross);
printf("taxes: $%.2f \n", taxes);
printf("net: $%.2f \n", net);
break;
case 5:
return 0;
default:
printf("Invalid choice, please enter the number that corresponds ");
printf("to your rate or press 5 to quit.\n\n");
}
system("PAUSE");
return 0;
}
您需要choice在每个步骤中更新的值。因此，我将编写类似以下内容的代码：
int main(void)
{
// some code
int choice;
bool loop = true;
while(loop)
{
printf("\n\nMenu\n----------\n\n");
// print the menu
printf("Enter the number that corresponds to your rate or press 5 to quit.\n");
scanf_s("%d", &choice);
switch (choice) {
// cases 1-4
case 5:
loop = false;
break;
default:
printf("Invalid choice.\n\n");
} // exit from switch
} // exit from while-loop
return 0;
}
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