我有以下内容:
{foreach key=num item=invoice from=$invoices}
<tr>
<td class="text-center"><a href="viewinvoice.php?id={$invoice.id}">#{$invoice.invoicenum}</a></td>
<td>{$invoice.datecreated}</td>
<td>{$invoice.datedue}</td>
<td data-order="{$invoice.totalnum}">{$invoice.total}</td>
<td class="text-center">{include file="$template/includes/status-pages/status-faturas.tpl"}</td>
<td class="text-center">
{if $invoice.rawstatus eq 'paid'}
{foreach from=$nfseData item=items}
{if $items.title|substr:16:4 eq $invoice.id && in_array($items.status, ['Answered', 'Closed'])}
<a href="{$WEB_ROOT}/dl.php?type=a&id={$items.id}&i=0" class="btn-sm rounded p-2 btn-success has-ripple"><i class="feather mr-1 icon-download"></i> Download NFS-e</a>
{elseif !in_array($items.status, ['Answered', 'Closed'])}
<a href="#!" class="btn-sm rounded p-2 btn-secondary has-ripple disabled"><i class="feather icon-refresh-cw mr-1"></i> Em processamento</a>
{else}
<a href="{$WEB_ROOT}/submitticket.php?step=2&deptid=27&subject=NFS-e%20|%20Fatura%20#xxx%20|%20Valor%20R$xxxx" class="btn-sm rounded p-2 btn-primary has-ripple"><i class="feather icon-layout mr-1"></i> Solicitar NFS-e</a>
{/if}
{/foreach}
{else}
<strong>N/D</strong>
{/if}
</td>
<td class="text-center"><a href="viewinvoice.php?id={$invoice.id}" class="btn-sm rounded p-2 btn-info has-ripple"><i class="feather mr-1 icon-eye"></i> Ver fatura</a></td>
</tr>
{/foreach}
html的返回:
<div>
<span>No - 1030</span>
<span>Yes - 1020</span>
</div>
<div>
<span>No - 1030</span>
<span>No - 1020</span>
</div>
我需要它像这样返回:
<div>
<span>Yes - 1020</span>
</div>
<div>
<span>No - 1030</span>
</div>
数组用于: $invoices
Array (4)
0 => Array (13)
id => 1020
rawstatus => "paid"
1 => Array (13)
id => 1030
rawstatus => "unpaid"
数组用于: $nfseData
Array (2)
0 => Array (27)
id => 6446
title => "NFS-e | Fatura #1020 | Valor R$59,90"
1 => Array (27)
id => 6445
title => "NFS-e | Fatura #1030 | Valor R$39,90"
问题是的返回from=$nfseData
有多个记录,在这种情况下,它是在不遵循此规则的情况下复制行:{if $items.title|substr:16:4 eq $invoice.id}
我需要它仅返回对于该规则为正的值,即具有相同数字的值。
有没有可能将此规则直接放入foreach
以便仅返回遵守该规则的行?还是有其他方法?
您正在遍历每个发票的所有项目。您正在向他们显示它们是否属于该对象invoice
。您可以将status
过滤器嵌套在if
其中,以检查invoice id
是否匹配,如果不匹配则不显示。
{foreach key=num item=invoice from=$invoices}
<tr>
<td class="text-center"><a href="viewinvoice.php?id={$invoice.id}">#{$invoice.invoicenum}</a></td>
<td>{$invoice.datecreated}</td>
<td>{$invoice.datedue}</td>
<td data-order="{$invoice.totalnum}">{$invoice.total}</td>
<td class="text-center">{include file="$template/includes/status-pages/status-faturas.tpl"}</td>
<td class="text-center">
{if $invoice.rawstatus eq 'paid'}
{foreach from=$nfseData item=items}
{if $items.title|substr:16:4 eq $invoice.id}
{if in_array($items.status, ['Answered', 'Closed'])}
<a href="{$WEB_ROOT}/dl.php?type=a&id={$items.id}&i=0" class="btn-sm rounded p-2 btn-success has-ripple"><i class="feather mr-1 icon-download"></i> Download NFS-e</a>
{elseif $items.status eq 'Open'}
<a href="#!" class="btn-sm rounded p-2 btn-secondary has-ripple disabled"><i class="feather icon-refresh-cw mr-1"></i> Em processamento</a>
{else}
<a href="{$WEB_ROOT}/submitticket.php?step=2&deptid=27&subject=NFS-e%20|%20Fatura%20#xxx%20|%20Valor%20R$xxxx" class="btn-sm rounded p-2 btn-primary has-ripple"><i class="feather icon-layout mr-1"></i> Solicitar NFS-e</a>
{/if}
{/if}
{/foreach}
{else}
<strong>N/D</strong>
{/if}
</td>
<td class="text-center"><a href="viewinvoice.php?id={$invoice.id}" class="btn-sm rounded p-2 btn-info has-ripple"><i class="feather mr-1 icon-eye"></i> Ver fatura</a></td>
</tr>
{/foreach}
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