我正在尝试编写一个程序,该程序将提示用户输入1到9之间的数字,并创建一个x矩阵x,其中x是给定的数字。它应该产生从1到x ^ 2的随机数以填充矩阵。我计算出在哪里,如果我输入“ 5”,我将得到一行包含5个随机数字,然后是四行,每个行仅包含一个数字。我想念什么?
import java.util.Scanner;
import java.util.Random;
public class MatrixFiller
{
public static void main(String[] args)
{
//Getting input from the user
Scanner input = new Scanner(System.in);
System.out.print("Size of Matrix(a number between 1 and 9): ");
int matrixn = input.nextInt();
input.close();
//max is the largest possible number that can be calculated
//with the given number squared.
int max = (matrixn * matrixn);
//Counters for building the matrix
int i = 0;
int j = 0;
//Will create a line with x numbers on it but then produces
//x lines with only one number. If given 5 it produces a
//line with 5 numbers then four more lines with one number
//each.
do {
do {
Random rand = new Random();
int mout = rand.nextInt(max - 0);
System.out.print(mout + " ");
i++;
}
while (i < matrixn);
System.out.println();
j++;
}
while (j < matrixn);
}
}
您需要i
在循环开始时进行重置,否则仍然matrixn
从上一行开始进行重置。
do {
i = 0; // It won't work without this
do {
Random rand = new Random();
int mout = rand.nextInt(max - 0);
System.out.print(mout + " ");
i++;
} while (i < matrixn);
System.out.println();
j++;
} while (j < matrixn);
虽然这可行,但最好使用for
循环来代替。
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