我知道，*是0以上，并且+是1或更多，但如果我想要的东西，表示2个或多个（大于1）？
例如，我有
>>> y = 'U0_0, P33, AVG'
>>> re.findall(r'[a-zA-Z]+', y)
['U', 'P', 'AVG']
但是我只想获取包含2个或更多字母的字母。在此示例中，AVG。
我该怎么做呢？
y = 'U0_0, P33, AVG'
print re.findall(r'[a-zA-Z]{2,}', y)
^^^
{m,n} Causes the resulting RE to match from m to n repetitions of the preceding RE, attempting to match as many repetitions as possible. For example, a{3,5} will match from 3 to 5 'a' characters. Omitting m specifies a lower bound of zero, and omitting n specifies an infinite upper bound. As an example, a{4,}b will match aaaab or a thousand 'a' characters followed by a b, but not aaab. The comma may not be omitted or the modifier would be confused with the previously described form.
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