需要比较两个字符串以仅在第5个索引处的唯一字符不同(忽略前4个字符)的情况下获得PAIR ...在mysql中,可以通过INBXOLC800Y = INBX_LC800Y(使用'_'通配符)来实现,但是如何在PHP中执行此操作...这是我现在的代码,但是我想可能会有更聪明和/或更短的方法???
$first_sku_full= "INBXOLC800Y";
$first_sku_short= substr($first_sku_full, 5); // gives LC800Y
$second_sku_full= "INBXPLC800Y";
$second_sku_short= substr($second_sku_full, 5); // gives LC800Y
if ( $first_sku_short == $second_sku_short ) {
// 6th character onward is matched now included 5th character
$first_sku_short= substr($first_sku_full, 4);
$second_sku_short= substr($second_sku_full, 4);
if ( $first_sku_short != $second_sku_short ) {
echo "first and second sku is a pair";
}else{
echo "first and second sku is NOT a pair;
}
}
您可以通过不分配所有这些变量来缩短它,只需测试中的子字符串即可if
。
if (substr($first_sku_full, 5) == substr($second_sku_full, 5)) {
if ($first_sku_full[4] != $second_sku_full[4])
echo "first and second sku are a pair";
} else {
echo "first and second sku are NOT a pair";
}
}
本文收集自互联网,转载请注明来源。
如有侵权,请联系 [email protected] 删除。
我来说两句