是的,这是家庭作业。我只是想了解为什么这似乎行不通。
我正在尝试按字母顺序查找字符串中最长的子字符串。我列出了一个随机字母列表,并说长度为19。在运行代码时,它会打印出索引0到17。(我知道发生这种情况是因为我从范围中减去1)但是,当我将其省略时- 1,它告诉我“字符串索引超出范围”。为什么会这样呢?
s = 'cntniymrmbhfinjttbiuqhib'
sub = ''
longest = []
for i in range(len(s) - 1):
if s[i] <= s[i+1]:
sub += s[i]
longest.append(sub)
elif s[i-1] <= s[i]:
sub += s[i]
longest.append(sub)
sub = ' '
else:
sub = ' '
print(longest)
print ('Longest substring in alphabetical order is: ' + max(longest, key=len))
我也尝试了其他一些方法
如果我只是说:
for i in s:
它将引发错误,并说“字符串索引必须是整数,而不是str。” 这似乎是一种遍历字符串的简单得多的方法,但是我将如何以这种方式比较各个字母呢?
顺便说一下,这是Python 2.7。
编辑:我确定我的if / elif语句可以改进,但这是我想到的第一件事。如有需要,我可以稍后再谈。
我确信我的if / elif语句可以改进,但这是我首先想到的。如有需要,我可以稍后再谈。
@ or1426的解决方案创建当前最长排序序列的列表,并将其复制到longest
发现更长序列的位置。每当找到更长的序列时,都会创建一个新列表,并将其添加到每个字符的列表中。在Python中,这实际上非常快,但请参见下文。
@Deej的解决方案将当前最长的排序序列保留在字符串变量中,并且每次找到更长的子字符串(即使是当前序列的延续)时,该子字符串也会保存到列表中。该列表最终具有原始字符串的所有已排序子字符串,并且通过调用来找到最长的子字符串max
。
这是一个更快的解决方案,它仅跟踪当前最大序列的索引,并且仅在找到未排序顺序的字符时才将更改最长。
def bjorn4(s):
# we start out with s[0] being the longest sorted substring (LSS)
longest = (0, 1) # the slice-indices of the longest sorted substring
longlen = 1 # the length of longest
cur_start = 0 # the slice-indices of the *current* LSS
cur_stop = 1
for ch in s[1:]: # skip the first ch since we handled it above
end = cur_stop-1 # cur_stop is a slice index, subtract one to get the last ch in the LSS
if ch >= s[end]: # if ch >= then we're still in sorted order..
cur_stop += 1 # just extend the current LSS by one
else:
# we found a ch that is not in sorted order
if longlen < (cur_stop-cur_start):
# if the current LSS is longer than longest, then..
longest = (cur_start, cur_stop) # store current in longest
longlen = longest[1] - longest[0] # precompute longlen
# since we can't add ch to the current LSS we must create a new current around ch
cur_start, cur_stop = cur_stop, cur_stop+1
# if the LSS is at the end, then we'll not enter the else part above, so
# check for it after the for loop
if longlen < (cur_stop - cur_start):
longest = (cur_start, cur_stop)
return s[longest[0]:longest[1]]
快多少?它的速度几乎是orl1426的两倍,是deej的三倍。与往常一样,这取决于您的输入。存在的排序子字符串块越多,上述算法与其他算法相比将越快。例如,在长度为100000的输入字符串中,包含交替的100个随机字符和100个有序字符,我得到:
bjorn4: 2.4350001812
or1426: 3.84699988365
deej : 7.13800001144
如果我将其更改为交替使用1000个随机字符和1000个排序的字符,那么我得到:
bjorn4: 23.129999876
or1426: 38.8380000591
deej : MemoryError
更新:这是我的算法的进一步优化版本,带有比较代码:
import random, string
from itertools import izip_longest
import timeit
def _randstr(n):
ls = []
for i in range(n):
ls.append(random.choice(string.lowercase))
return ''.join(ls)
def _sortstr(n):
return ''.join(sorted(_randstr(n)))
def badstr(nish):
res = ""
for i in range(nish):
res += _sortstr(i)
if len(res) >= nish:
break
return res
def achampion(s):
start = end = longest = 0
best = ""
for c1, c2 in izip_longest(s, s[1:]):
end += 1
if c2 and c1 <= c2:
continue
if (end-start) > longest:
longest = end - start
best = s[start:end]
start = end
return best
def bjorn(s):
cur_start = 0
cur_stop = 1
long_start = cur_start
long_end = cur_stop
for ch in s[1:]:
if ch < s[cur_stop-1]:
if (long_end-long_start) < (cur_stop-cur_start):
long_start = cur_start
long_end = cur_stop
cur_start = cur_stop
cur_stop += 1
if (long_end-long_start) < (cur_stop-cur_start):
return s[cur_start:cur_stop]
return s[long_start:long_end]
def or1426(s):
longest = [s[0]]
current = [s[0]]
for char in s[1:]:
if char >= current[-1]: # current[-1] == current[len(current)-1]
current.append(char)
else:
current=[char]
if len(longest) < len(current):
longest = current
return ''.join(longest)
if __name__ == "__main__":
print 'achampion:', round(min(timeit.Timer(
"achampion(rstr)",
setup="gc.enable();from __main__ import achampion, badstr; rstr=badstr(30000)"
).repeat(15, 50)), 3)
print 'bjorn:', round(min(timeit.Timer(
"bjorn(rstr)",
setup="gc.enable();from __main__ import bjorn, badstr; rstr=badstr(30000)"
).repeat(15, 50)), 3)
print 'or1426:', round(min(timeit.Timer(
"or1426(rstr)",
setup="gc.enable();from __main__ import or1426, badstr; rstr=badstr(30000)"
).repeat(15, 50)), 3)
输出:
achampion: 0.274
bjorn: 0.253
or1426: 0.486
将数据更改为随机数据:
achampion: 0.350
bjorn: 0.337
or1426: 0.565
并排序:
achampion: 0.262
bjorn: 0.245
or1426: 0.503
“不,不,它还没死,它正在休息”
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我来说两句