我收集了如下文档:
{
"_id" : ObjectId("55d4410544c96d6f6578f893"),
"executionProject" : "Project1",
"suiteList" : [
{
"suiteStatus" : "PASS"
}
],
"runEndTime" : ISODate("2015-08-19T08:40:47.049Z"),
"runStartTime" : ISODate("2015-08-19T08:40:37.621Z"),
"runStatus" : "PASS",
"__v" : 1
}
{
"_id" : ObjectId("55d44eb4c0422e7b8bffe76b"),
"executionProject" : "Project1",
"suiteList" : [
{
"suiteStatus" : "PASS"
}
],
"runEndTime" : ISODate("2015-08-19T09:39:13.528Z"),
"runStartTime" : ISODate("2015-08-19T09:39:00.406Z"),
"runStatus" : "PASS",
"__v" : 1
}
{
"_id" : ObjectId("55d44f0bc0422e7b8bffe76f"),
"executionProject" : "Project1",
"suiteList" : [
{
"suiteStatus" : "FAIL"
}
],
"runEndTime" : ISODate("2015-08-19T09:46:31.108Z"),
"runStartTime" : ISODate("2015-08-19T09:40:27.377Z"),
"runStatus" : "PASS",
"__v" : 1
}
{
"_id" : ObjectId("55d463d0c0422e7b8bffe789"),
"executionProject" : "Project2",
"suiteList" : [
{
"suiteStatus" : "PASS"
},
{
"suiteStatus" : "PASS"
}
],
"runEndTime" : ISODate("2015-08-19T11:09:52.537Z"),
"runStartTime" : ISODate("2015-08-19T11:09:04.539Z"),
"runStatus" : "FAIL",
"__v" : 1
}
{
"_id" : ObjectId("55d464ebc0422e7b8bffe7c2"),
"executionProject" : "Project3",
"suiteList" : [
{
"suiteStatus" : "FAIL"
}
],
"runEndTime" : ISODate("2015-08-19T11:18:41.460Z"),
"runStartTime" : ISODate("2015-08-19T11:13:47.268Z"),
"runStatus" : "FAIL",
"__v" : 10
}
我期望输出如下:
[
{
"executionProject": "Project1",
"suite-pass": 0,
"suite-fail": 1,
"runEndTime": ISODate("2015-08-19T09:46:31.108Z")
},
{
"executionProject": "Project2",
"suite-pass": 2,
"suite-fail": 0,
"runEndTime": ISODate("2015-08-19T11:09:52.537Z")
},
{
"executionProject": "Project3",
"suite-pass": 0,
"suite-fail": 1,
"runEndTime": ISODate("2015-08-19T11:18:41.460Z")
},
]
我想按项目分组并按runEndTime排序,并显示suiteList的通过和失败计数。
我尝试了Blakes在Mongodb中建议的方法:按元素分组,并根据条件显示子文档计数,并按日期对文档进行排序:
db.testruns.aggregate([
{ "$sort": { "runEndTime": 1 } },
{ "$group": {
"_id": "$executionProject",
"suite-pass": {
"$last": {
"$cond": [
{ "$anyElementTrue": {
"$map": {
"input": "$suiteList",
"as": "suite",
"in": {
"$eq": [ "$$suite.suiteStatus", "PASS" ]
}
}
}},
1,
0
]
}
},
"suite-fail": {
"$last": {
"$cond": [
{ "$anyElementTrue": {
"$map": {
"input": "$suiteList",
"as": "suite",
"in": {
"$eq": [ "$$suite.suiteStatus", "FAIL" ]
}
}
}},
1,
0
]
}
},
"runEndTime": { "$last": "$runEndTime" }
}},
{ "$sort": { "runEndTime": 1 } }
]);
我期望suite-pass
计数为Project2
2,因为suiteList中有2个元素,但它返回1。
您应该已经正确地阅读了答案,因为已经有了另一个替代清单,并解释了为什么您想要的预期结果与您使用的预期结果会有所不同。
取而代之的是您想要这样的一个,它尊重可能的多个“ PASS”或“ FAIL”:
Model.aggregate(
[
{ "$sort": { "executionProject": 1, "runEndTime": 1 } },
{ "$group": {
"_id": "$executionProject",
"suiteList": { "$last": "$suiteList" },
"runEndTime": { "$last": "$runEndTime" }
}},
{ "$unwind": "$suiteList" },
{ "$group": {
"_id": "$_id",
"suite-pass": {
"$sum": {
"$cond": [
{ "$eq": [ "$suiteList.suiteStatus", "PASS" ] },
1,
0
]
}
},
"suite-fail": {
"$sum": {
"$cond": [
{ "$eq": [ "$suiteList.suiteStatus", "FAIL" ] },
1,
0
]
}
},
"runEndTime": {"$first": "$runEndTime"}
}},
{ "$sort": { "runEndTime": 1 }}
],
function(err,result) {
}
);
这是方法的“组合”。首先是按照您的期望在运行时获得“最后”。接下来是分解阵列,这次实际上是“总结”通过或失败的可能发生,而不是仅1
在阵列中记录通过或失败的a,而是计算实际的“通过”或“失败”。
结果:
{
"_id" : "Project1",
"suite-pass" : 0,
"suite-fail" : 1,
"runEndTime" : ISODate("2015-08-19T09:46:31.108Z")
}
{
"_id" : "Project2",
"suite-pass" : 2,
"suite-fail" : 0,
"runEndTime" : ISODate("2015-08-19T11:09:52.537Z")
}
{
"_id" : "Project3",
"suite-pass" : 0,
"suite-fail" : 1,
"runEndTime" : ISODate("2015-08-19T11:18:41.460Z")
}
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