我上课,目的是从Git提交中获取用户名和他的电子邮件:
class BitbucketData(object):
def get_user_name(self):
proc = subprocess.Popen("git --no-pager show -s --format='%an'", stdout=subprocess.PIPE)
committer_name = proc.stdout.read()
if committer_name:
return committer_name
def get_user_email(self):
proc = subprocess.Popen("git --no-pager show -s --format='%aE'", stdout=subprocess.PIPE)
committer_email = proc.stdout.read()
if committer_email:
return committer_email
它使用,那么发送通知用户(底部工作版本-没有变量-所有sender
与receiver
数据集明确,不变量-他们在这里评论):
class Services(object):
def sendmail(self, event):
repo = BitbucketData()
#to_address = repo.get_user_email()
#to_address = '[email protected]'
#to_name = repo.get_user_name()
#to_name = 'Test user'
subject = 'Bamboo build and deploy ready'
sender = 'Bamboo agent <[email protected]>'
text_subtype = 'plain'
message = """
Hello, {}.
Your build ready.
Link to scenario: URL
Link to build and deploy results: {})
""".format('Test user', os.environ['bamboo_resultsUrl'])
msg = MIMEText(message, text_subtype)
msg['Subject'] = subject
msg['From'] = sender
msg['To'] = 'Test user <[email protected]>'
smtpconnect = smtplib.SMTP('outlook.office365.com', 587)
smtpconnect.set_debuglevel(1)
smtpconnect.starttls()
smtpconnect.login('[email protected]', 'password')
smtpconnect.sendmail('[email protected]', '[email protected]', msg.as_string())
smtpconnect.quit()
print('Mail sent')
print(repo.get_user_email())
问题是-如果我正在使用变量中的数据(例如,to_address = '[email protected]'
或将BitbucketData()
类与to_address = repo.get_user_email()
-一起使用)-我收到了Office365服务器的错误消息:
... reply: '250 2.1.0 Sender OK\r\n' reply: retcode (250); Msg: 2.1.0 Sender OK send: "rcpt TO:<'[email protected]'>\r\n" reply: '501 5.1.3 Invalid address\r\n' reply: retcode (501); Msg: 5.1.3 Invalid address ... File "C:\Python27\lib\smtplib.py", line 742, in sendmail raise SMTPRecipientsRefused(senderrs) smtplib.SMTPRecipientsRefused: {"'[email protected]'\n": (501, '5.1.3 Invalid address')}
使用变量时,代码如下所示:
class Services(object):
def sendmail(self, event):
repo = BitbucketData()
to_address = repo.get_user_email()
#to_address = '[email protected]'
to_name = repo.get_user_name()
#to_name = 'Test user'
from_address = '[email protected]'
subject = 'Bamboo build and deploy ready'
sender = 'Bamboo agent <[email protected]>'
text_subtype = 'plain'
message = """
Hello, {}.
Your build ready.
Link to scenario: URL
Link to build and deploy results: {})
""".format(to_name, os.environ['bamboo_resultsUrl'])
msg = MIMEText(message, text_subtype)
msg['Subject'] = subject
msg['From'] = sender
msg['To'] = to_name
smtpconnect = smtplib.SMTP('outlook.office365.com', 587)
smtpconnect.set_debuglevel(1)
smtpconnect.starttls()
smtpconnect.login('[email protected]', 'password')
smtpconnect.sendmail(from_address, to_address, msg.as_string())
smtpconnect.quit()
print('Mail sent')
print(repo.get_user_email())
我在这里(或Microsoft SMTP ...)做错了什么?
UPD
def sendmail(self, event):
repo = BitbucketData()
print(repr(repo.get_user_email()))
...
给我:
... Creating new AutoEnv config "'[email protected]'\n" send: 'ehlo pc-user.kyiv.domain.net\r\n' ...
似乎您从git命令接收以下内容作为输出-
"'[email protected]'\n"
您直接将其传递给smtpconnect,这是引起问题的原因,因为这不是有效的电子邮件地址。您可能需要从中获取实际的字符串。获得它的一种方法是为此使用ast.literal_eval()
函数。例子 -
>>> import ast
>>> e = ast.literal_eval("'[email protected]'\n")
>>> print(e)
[email protected]
从get_user_email()
函数返回电子邮件时,您需要执行此操作。最有可能committer_name
也是这个问题,因此您可能也想这样做。
来自ast.literal_eval()
-的文档
ast.literal_eval(node_or_string)
安全地评估包含Python文字或容器显示的表达式节点或Unicode或Latin-1编码的字符串。提供的字符串或节点只能由以下Python文字结构组成:字符串,数字,元组,列表,字典,布尔值和无。
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我来说两句