批处理脚本可根据当前的父名称将特定的子文件夹移动到新的父文件夹中

在您的测试目录中尝试以下操作：

 FOR /D %d IN (*\ProjectYear2014\) DO (MOVE %d\ProjectYear2014\ C:\HistoricProjects\%d\ProjectYear2014 )

该命令的基础是：

 FOR /D %d IN             :: for directories, store matches in variable %d
 (*\ProjectYear2014\)     :: that are located in (anything)\ProjectYear2014
 DO (MOVE %d\ProjectYear2014\               :: Move target (match)\... 
 C:\HistoricProjects\%d\ProjectYear2014 )   :: To new directory ...

我只是想解释一下，::这相当于DOS中的注释，但是对它们却非常挑剔。绝对不要在代码块内（例如，在FOR块内）使用注释，并且如果您尝试使命令像第二个示例一样跨多行，则CMD会阻塞。我只是用这种方式写的，以帮助解释发生了什么。

这是您已经拥有的代码：

@echo off 
Set /P YEAR=Project Year to move? 
FOR %%A IN (ATTRIB C:\ActiveTest*\"ProjectYear %YEAR%") DO 
::I can't figure out how to make DIR look back and only pull the 2nd level into a variable.
::If I can get that I figure I can work it into a ROBOCOPY somehow.

结合它们，您的最终结果将是这样，但可能不完全是这样：

@echo off 
Set /P YEAR=Project Year to move? 
FOR /D %d IN (C:\CurrentProjects\*\ProjectYear%YEAR%\) DO (MOVE C:\CurrentProjects\%d\ProjectYear%YEAR%\ C:\HistoricProjects\%d\ProjectYear%YEAR%\ )

ew，对我来说，这是一个学习过程。